document.write( "Question 1191699: A man invested P140,000. Part of his capital was invested at 11% and the rest at 9%. If the total income of the investments is P13,900, how much was invested at each rate?
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Algebra.Com's Answer #823498 by Theo(13342)\"\" \"About 
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x = the amount invested at 11%.
\n" ); document.write( "y = the amount invested at 9%.\r
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\n" ); document.write( "\n" ); document.write( "your equations are:\r
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\n" ); document.write( "\n" ); document.write( "x + y = 140,000
\n" ); document.write( ".11x + .09y = 13,900\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by .11 and leave the second equation as it to get:\r
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\n" ); document.write( "\n" ); document.write( ".11x + .11y = 15,400
\n" ); document.write( ".11x + 09y = 13,900\r
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\n" ); document.write( "\n" ); document.write( "subtract the second equation from the first to get:\r
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\n" ); document.write( "\n" ); document.write( ".02y = 1,500\r
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\n" ); document.write( "\n" ); document.write( "solve for y to get:
\n" ); document.write( "y = 1,500 / .02 = 75,000\r
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\n" ); document.write( "\n" ); document.write( "this means that x = 140,000 - 75,000 = 65,000.
\n" ); document.write( "this also means that .11 * x = .11 * 65,000 = 7,150.
\n" ); document.write( "this also means that .09 * y = .09 * 75,000 = 6,750.\r
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\n" ); document.write( "\n" ); document.write( "total income is 7,150 + 6,750 = 13,900.
\n" ); document.write( "total invested is 65,000 + 75,000 = 140,000.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that 65,000 was invested at 11% and 75,000 was invested at 9%.\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions or concerns.
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