document.write( "Question 1191697: 3. Given: The mean is 78.5, the standard deviation is 6.2, calculate the CV. \n" ); document.write( "
Algebra.Com's Answer #823497 by Theo(13342)![]() ![]() You can put this solution on YOUR website! here's a reference on CV which, i believe, is called the coefficient of variation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.investopedia.com/terms/c/coefficientofvariation.asp#:~:text=Key%20Takeaways-,The%20coefficient%20of%20variation%20(CV)%20is%20a%20statistical%20measure%20of,of%20return%20expected%20from%20investments.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on this reference, it is the standard deviation divided by the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your problem gives the mean as 78.5 with a standard deviation of 6.2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the CV would be equal to standard deviation / mean = 6.2 / 78.5 = .0789808917.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "round as required.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |