document.write( "Question 1191685: The marks in English in a recent test had a mean of 76% with a standard deviation of 7%. The Science results had a mean of 84% with a standard deviation of 5%. Jasmine obtained scores of 86% in English and 89% in Science.\r
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document.write( "a) Which is the better result? Explain your answer.
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document.write( "b) If there are 30 people in the class, estimate Jasmine's position in Science. \n" );
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Algebra.Com's Answer #823483 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the marks in english have a mean of 76% with a standard deviation of 7%. \n" ); document.write( "the marks in science have a mean of 84% with a standard deviation of 5%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jasmine obtained 86% in english and 89% in science.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use the z-score to compare these.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score formula says z = (x - m) / s \n" ); document.write( "z is the z-score \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation, in this case.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for english, her z-score formula becomes z = (86 - 76) / 7 = 1.43, rounded to 2 decimal places. \n" ); document.write( "for science, her z-score formula becomes z = (89 - 84) / 5 = 1, no additional rounding required.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a z-score of 1.43 has a greater area under the normal distribution curve to the left of it. \n" ); document.write( "this indicates she scored higher, relative to her peers, in the english course. \n" ); document.write( "while she had a higher score in science, the rest of the class did better too, making her score less higher, relative to her peers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "fyi, a z-score of 1.43 has an area under the normal distribution curve equal to \n" ); document.write( ".92364 to the left of it and a z-score of 1 has an area under the normal distribution curve equal to .84134.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "an area of .92364 to the left of the z-score means she was better than approximately 92% of her peers in english. \n" ); document.write( "an area of .84134 to the left of the z-score means she was better than approximately 84% of her peers in science.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let me know if you have any questions. \n" ); document.write( "theo\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |