document.write( "Question 1191549: Kevin has money in two savings accounts. One rate is 6% and the other is 12%. If he has $600 more in the 12% account and the total interest is $279, how much is invested in each savings account? \n" ); document.write( "

Algebra.Com's Answer #823343 by ikleyn(52908) $\"\"$ $\"About$

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\n" ); document.write( "Kevin has money in two savings accounts. One rate is 6% and the other is 12%.
\n" ); document.write( "If he has $600 more in the 12% account and the total interest is $279,
\n" ); document.write( "how much is invested in each savings account?
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document.write( "x = the amount saved at 12%;  \r\n" );
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document.write( "y = the amount saved at 6%.\r\n" );
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document.write( "From the condition, you have these two equations\r\n" );
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document.write( "    x     -     y = 600   dollars     (1)\r\n" );
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document.write( "    0.12x + 0.06y = 279   dollars     (2)\r\n" );
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document.write( "To solve this system, express x = y + 600 from equation (1) and substitute it into equation (2).  You will get\r\n" );
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document.write( "    0.12(y+600) - 0.06y = 279\r\n" );
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document.write( "    0.12y + 0.12*600 + 0.06y = 279\r\n" );
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document.write( "    0.12y + 0.06y            = 279 - 0.12*600\r\n" );
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document.write( "         0.18y               = 207\r\n" );
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document.write( "             y               = 207/0.18 = 1150.\r\n" );
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document.write( "Then from equation (1),\r\n" );
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document.write( "    x = 600 + 1150 = 1750.\r\n" );
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document.write( "ANSWER.  $1750 invested at 12%  and  $1150 invested at 6%.\r\n" );
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document.write( "CHECK.  I will check equation (2).   Its left side is  0.12*1750 + 0.06*1150 = 279  dollars.   ! Correct !\r\n" );
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