document.write( "Question 1191524: 3. Marks of 75 students are summarized in the following frequency distribution:
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document.write( "Marks 40 - 44 45 - 49 50 - 54 55 - 59 60 - 64 65 - 69 70 - 74
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document.write( "No. of students 7 10 22 F4 F5 6 3
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document.write( "If 20% of the students have marks between 55 and 59
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document.write( "i. Find the missing frequencies f4 and f5.
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document.write( "ii. Find the mean, median and mode
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Algebra.Com's Answer #823325 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part (i) \n" ); document.write( "Original Table: \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20% of all 75 students have marks between 55 and 59. \n" ); document.write( "20% of 75 = 0.20*75 = 15 \n" ); document.write( "The number 15 replaces F4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be the value of F5 \n" ); document.write( "The items in the frequency column must add to 75 \n" ); document.write( "7 + 10 + 22 + 15 + x + 6 + 3 = 75 \n" ); document.write( "x+63 = 75 \n" ); document.write( "x = 75-63 \n" ); document.write( "x = 12 \n" ); document.write( "The number 12 replaces F5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Updated Table: \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==========================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (ii)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The class interval 40 to 44 has the midpoint (A+B)/2 = (40+44)/2 = 84/2 = 42 \n" ); document.write( "Through similar calculations, the midpoint of the interval 45 to 49 is 47. \n" ); document.write( "This process is carried out until you address each interval.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The midpoints in order from left to right are: 42, 47, 52, 57, 62, 67, 72 \n" ); document.write( "The midpoints are increasing by 5 each time, which is exactly the gap from each left endpoint of adjacent classes (same goes for the right endpoints as well).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll add the row of midpoints which I'll refer to as M \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For each column, we'll multiply the frequency value f with its corresponding midpoint M \n" ); document.write( "Eg: the first column has 7*42 = 294 \n" ); document.write( "
\n" ); document.write( "Adding up the values in that bottom row gets us \n" ); document.write( "294 + 470 + 1144 + 855 + 744 + 402 + 216 = 4125\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide that over the total number of students (75) \n" ); document.write( "4125/75 = 55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The mean is 55.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are an odd number of students (75) \n" ); document.write( "75/2 = 37.5 this rounds to 38 \n" ); document.write( "The median is in slot 38. The first 37 items are below it, the upper 37 items are above the median. \n" ); document.write( "That gives 37+1+37 = 75 scores total.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Clearly the median is not in class 40-44 since we only have 7 students here. \n" ); document.write( "The median is also not in the 45-49 class because 7+10 = 17 is too small also \n" ); document.write( "7+10+22 = 39 is now too large since we want to land on 38.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The median mark is somewhere between 50 and 54. \n" ); document.write( "We don't have enough info to determine its exact value because of the grouped nature of the marks.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The mode is the most frequent score. \n" ); document.write( "The largest frequency is 22 and it occurs for the 50-54 class. \n" ); document.write( "Like with the median, we can't pinpoint its exact value. \n" ); document.write( "It's possible that the median = mode, but it's not a guarantee.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answers: \n" ); document.write( "Mean = 55 \n" ); document.write( "Median = somewhere between 50 and 54. \n" ); document.write( "Mode = somewhere between 50 and 54. \n" ); document.write( " \n" ); document.write( " |