document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191506>Question 1191506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "You are painting the surface of a silo of radius 8 ft and height 50ft. What is the total surface area to be painted. Assume the top is a hemisphere and that the silo sits on the ground. Use pi = 3.14.<BR>\n" );
document.write( "Thanks. </SPAN>\n" );
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document.write( "hemisphere = half a sphere\r<BR>\n" );
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document.write( "A full sphere has this surface area<BR>\n" );
document.write( "SA = 4*pi*r^2<BR>\n" );
document.write( "which makes 2pi*r^2 the surface area of a hemisphere (half as much as the previous expression)\r<BR>\n" );
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document.write( "Plug in r = 8 to find...<BR>\n" );
document.write( "SA = 2*pi*r^2<BR>\n" );
document.write( "SA = 2*pi*8^2<BR>\n" );
document.write( "SA = 128pi<BR>\n" );
document.write( "is the surface area of the hemispherical portion.\r<BR>\n" );
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document.write( "The cylindrical portion involves only the lateral surface area because the base isn't painted, and the top of the cylinder is covered by the hemisphere.<BR>\n" );
document.write( "We only consider the curved side.\r<BR>\n" );
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document.write( "LSA = lateral surface area<BR>\n" );
document.write( "LSA of cylinder = 2*pi*r*h<BR>\n" );
document.write( "LSA of cylinder = 2*pi*8*50<BR>\n" );
document.write( "LSA of cylinder = 800pi\r<BR>\n" );
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document.write( "Combine the two surface area results:<BR>\n" );
document.write( "hemisphere + LSA = 128pi+800pi = 928pi\r<BR>\n" );
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document.write( "That's the exact surface area needed to be painted in terms of pi.<BR>\n" );
document.write( "Replace pi with 3.14 to find its approximate counterpart.<BR>\n" );
document.write( "928*pi = 928*3.14 = 2,913.92\r<BR>\n" );
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document.write( "Answer: 2913.92 square feet (approximate)<BR>\n" );
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