document.write( "Question 1191468: A police officer at the side of the highway sees a bank robber in the get-away vehicle speeding down the road at 35.0 m/s. The officer calls quickly for backup and then starts to follow the robber when the robber is 100. m away from her. If the officer starts from rest and accelerates at 1.40 m/s2, how far will she drive before she catches the robber? Include a diagram \r
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Algebra.Com's Answer #823291 by ikleyn(52813) $\"\"$ $\"About$

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\n" ); document.write( "A police officer at the side of the highway sees a bank robber in the get-away vehicle
\n" ); document.write( "speeding down the road at 35.0 m/s. The officer calls quickly for backup and then starts
\n" ); document.write( "to follow the robber when the robber is 100. m away from her.
\n" ); document.write( "If the officer starts from rest and accelerates at 1.40 m/s2,
\n" ); document.write( "how far will she drive before she catches the robber? Include a diagram
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document.write( "In this catching up problem, the governing equation is\r\n" );
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document.write( "    35t + 100 =     meters.\r\n" );
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document.write( "Simplify \r\n" );
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document.write( "    35t + 100 = \r\n" );
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document.write( "     - 35t - 100 = 0\r\n" );
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document.write( "Solve using the quadratic formula. Use the positive root.\r\n" );
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document.write( "ANSWER.  t= 52.71 seconds.\r\n" );
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