document.write( "Question 1191490: Calculate the sum:\r
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document.write( "1/4(1^3) + 1/9((1^3) + (2^3)) + 1/16((1^3) + (2^3) + (3^3)) +...+ 1/2704((1^3) + (2^3) + (3^3) +...+ (51^3)) \n" );
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Algebra.Com's Answer #823283 by greenestamps(13334) You can put this solution on YOUR website! \n" ); document.write( "The fractional part of the n-th term is \n" ); document.write( " \n" ); document.write( "The other factor in the n-th term is the sum of the cubes of the first n integers: \n" ); document.write( " \n" ); document.write( "So the nth term in the sequence is \n" ); document.write( " \n" ); document.write( "There are 51 terms in the sequence, so the sum is \n" ); document.write( " \n" ); document.write( "Use the formula for the sum of the first n squares to get the final answer. \n" ); document.write( " \n" ); document.write( "ANSWER: 22763/4 \n" ); document.write( " \n" ); document.write( " |