document.write( "Question 1191490: Calculate the sum:\r
\n" ); document.write( "\n" ); document.write( "1/4(1^3) + 1/9((1^3) + (2^3)) + 1/16((1^3) + (2^3) + (3^3)) +...+ 1/2704((1^3) + (2^3) + (3^3) +...+ (51^3))
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Algebra.Com's Answer #823283 by greenestamps(13334)\"\" \"About 
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\n" ); document.write( "The fractional part of the n-th term is

\n" ); document.write( "\"1%2F%28n%2B1%29%5E2\"

\n" ); document.write( "The other factor in the n-th term is the sum of the cubes of the first n integers:

\n" ); document.write( "\"sum%28%282n-1%29%5E3%2C1%2Cn%29=%28%28n%28n%2B1%29%29%2F2%29%5E2\"

\n" ); document.write( "So the nth term in the sequence is

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\n" ); document.write( "There are 51 terms in the sequence, so the sum is

\n" ); document.write( "\"%28sum%28n%5E2%2C1%2C51%29%2F4%29\"

\n" ); document.write( "Use the formula for the sum of the first n squares to get the final answer.

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\n" ); document.write( "ANSWER: 22763/4

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