document.write( "Question 113028: i have no idea how to solve this, can someone please help me? a silversmith has two alloys. the first alloy is 28% silver and the second is 60% silver. how many grams of each should be mixed to produce 80 grams of an alloy that is 52% silver? So i should have came up with 2 answers right? stumped! \n" ); document.write( "
Algebra.Com's Answer #82327 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
A = alloy #1
\n" ); document.write( "B = alloy #2
\n" ); document.write( "\".28A+%2B+.6B+=+.52%28A+%2B+B%29\"
\n" ); document.write( "\"A+%2B+B+=+80\"
\n" ); document.write( "\".28A+%2B+.6%2880+-+A%29+=+.52%2A80\"
\n" ); document.write( "\".28A+%2B+48+-+.6A+=+41.6\"
\n" ); document.write( "\"-.32A+=+-6.4\"
\n" ); document.write( "\"A+=+20\"grams of alloy #1
\n" ); document.write( "\"B+=+60\"grams of alloy #2
\n" ); document.write( "check answer
\n" ); document.write( "\".28A+%2B+.6B+=+.52%28A+%2B+B%29\"
\n" ); document.write( "\".28%2A20+%2B+.6%2A60+=+.52%2A80\"
\n" ); document.write( "\"5.6+%2B+36+=+41.6\"
\n" ); document.write( "\"41.6+=+41.6\"
\n" ); document.write( "OK
\n" ); document.write( "
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