document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191471>Question 1191471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carl and Dennie's are brothers. The sum of their ages is 29. In 6 year's time Carl will be same age as Dennis was 3 years ago. Write down the appropriate equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823251 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is ONE way to set up the problem for solving....<br><BR>\n" );
document.write( "let x = Carl's age<BR>\n" );
document.write( "then 29-x = Dennie's age<br><BR>\n" );
document.write( "Carl's age 6 years from now will be x+6<BR>\n" );
document.write( "Dennie's age 3 years ago was (29-x)-3 = 26-x<br><BR>\n" );
document.write( "In 6 year's time Carl will be same age as Dennie was 3 years ago:<br><BR>\n" );
document.write( "x+6 = 26-x<br><BR>\n" );
document.write( "That is ONE equation that can be used to solve the problem.<br><BR>\n" );
document.write( "Setting the problem up differently might lead to a very different equation....<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );