document.write( "Question 1191415: Roughly 1 in 6 students enrolled in higher education took at least one online course last fall. If 5 enrolled students are chosen at random, what is the probability that all 5 took online courses? What is the probability that at least 1 took an online course? \n" ); document.write( "
Algebra.Com's Answer #823226 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "Roughly 1 in 6 students enrolled in higher education took at least one online course last fall.
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document.write( "(a)  P = \"%281%2F6%29%5E5\" = \"1%2F6%5E5\" = \"1%2F7776\".    ANSWER\r\n" );
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document.write( "(b)  P = \"1+-+%285%2F6%29%5E5\" = \"1+-+3125%2F7776\" = \"%287776-3125%29%2F7776\" = \"4651%2F7776\" = 0.5981  (rounded).   ANSWER\r\n" );
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