document.write( "Question 1191411: if the price of kerosene is increased by $6 per litre, find the new price per litre if two-thirds of the new price is equal to five-sevenths of the old price \n" ); document.write( "
Algebra.Com's Answer #823199 by Theo(13342)\"\" \"About 
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x equals the new price.
\n" ); document.write( "y equals the old price.
\n" ); document.write( "x = y + 6
\n" ); document.write( "2/3 * x = 5/7 * y
\n" ); document.write( "multiply both sides of this equation by 3/2 to get:
\n" ); document.write( "x = 5/7 * 3/2 * y
\n" ); document.write( "simplify to get:
\n" ); document.write( "x = 15/14 * y
\n" ); document.write( "since x = y + 6, then you get:
\n" ); document.write( "y + 6 = 15/14 * y
\n" ); document.write( "subtract y from both sides of the equation to get:
\n" ); document.write( "6 = 15/14 * y - y
\n" ); document.write( "since 1 * y = 14 * y / 14, you get:
\n" ); document.write( "6 = 15/4 * y - 14/14 * y
\n" ); document.write( "simplify to get:
\n" ); document.write( "6 = 1/14 * y
\n" ); document.write( "solve for y to get:
\n" ); document.write( "y = 14 * 6 = 84
\n" ); document.write( "since x = y + 6, then you get:
\n" ); document.write( "x = 90
\n" ); document.write( "to confirm, you have:
\n" ); document.write( "x = y + 6 becomes 90 = 84 + 6 which is true.
\n" ); document.write( "2/3 * x = 5/7 * y becomes 2/3 * 90 = 5/7 * 84 which becomes 60 = 60 which is true.
\n" ); document.write( "this confirms the solution is correct.
\n" ); document.write( "the solution is that the new price is $90 per liter.\r
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