document.write( "Question 1191384: Simplify the following functions using a K-map\r
\n" ); document.write( "\n" ); document.write( "F(X, Y) = X + X’Y\r
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\n" ); document.write( "\n" ); document.write( "Could you please explain me this homework question step-by-step? Thank you!
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Algebra.Com's Answer #823196 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Thank you for posting one question at a time. I appreciate it.\r
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\n" ); document.write( "\n" ); document.write( "Here are the standard minterms for 2 variables only.
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Minterms
XYTermDesignation
00X'Y'm0
01X'Ym1
10XY'm2
11XYm3

\n" ); document.write( "The given boolean function
\n" ); document.write( "F(X,Y) = X + X'Y
\n" ); document.write( "needs to be rewritten in such a way that we involve only the minterms listed.\r
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\n" ); document.write( "\n" ); document.write( "That lone X needs to have a Y or Y' attached to it somehow.\r
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\n" ); document.write( "\n" ); document.write( "We have to do a bit of trickery to get the function to be a sum of standard minterms.
\n" ); document.write( "F(X,Y) = X + X'Y
\n" ); document.write( "F(X,Y) = X*1 + X'Y .... identity law
\n" ); document.write( "F(X,Y) = X*(Y+Y') + X'Y .... inverse law
\n" ); document.write( "F(X,Y) = X*Y + X*Y' + X'Y .... distributive law\r
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\n" ); document.write( "\n" ); document.write( "At this point, we have the boolean function written as the sum as these specific minterms
\n" ); document.write( "m3 = XY
\n" ); document.write( "m2 = XY'
\n" ); document.write( "m1 = X'Y
\n" ); document.write( "If we wanted, we could express that sum as F(X,Y) = m1+m2+m3 = Σ(1,2,3)\r
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\n" ); document.write( "\n" ); document.write( "This is the blank K-map for the two variables X and Y.
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\n" ); document.write( "Along the top we have 0 and 1 corresponding to either X' or X respectively.
\n" ); document.write( "Along the left side we have 0 and 1 corresponding to either Y' or Y respectively.
\n" ); document.write( "These rules apply to minterms only.\r
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\n" ); document.write( "\n" ); document.write( "Inside the table itself, we'll enter the m0 through m3 as shown below.
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\n" ); document.write( "Here's some informal notation to help keep track.
\n" ); document.write( "m0 = 00 = X'Y'
\n" ); document.write( "m1 = 01 = X'Y
\n" ); document.write( "m2 = 10 = XY'
\n" ); document.write( "m3 = 11 = XY
\n" ); document.write( "Or you could use the minterm table mentioned at the top of the page.\r
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\n" ); document.write( "\n" ); document.write( "Next, we replace m1,m2,m3 with 1's since they are part of the F(X,Y) function after we expanded things out.
\n" ); document.write( "The fact that m0 is left out means it gets assigned 0.
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\n" ); document.write( "\n" ); document.write( "Now comes the grouping.
\n" ); document.write( "Use these K-Map grouping rules
\n" ); document.write( "http://www.ee.surrey.ac.uk/Projects/Labview/minimisation/karrules.html
\n" ); document.write( "and you can review on this page if needed
\n" ); document.write( "http://www.ee.surrey.ac.uk/Projects/Labview/minimisation/karnaugh.html#introduction
\n" ); document.write( "There are a lot of rules to keep in mind, but once you get the hang of it, it's not too bad.\r
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\n" ); document.write( "\n" ); document.write( "The goal is to group the '1's together in batches of powers of 2. In this case, it means we either want groups of 1 or groups of 2.
\n" ); document.write( "The other goal is to minimize the number of groups, while also maximizing the group sizes.\r
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\n" ); document.write( "\n" ); document.write( "Doing both of those tasks can be achieved with this grouping here.
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\n" ); document.write( "Groups can overlap.
\n" ); document.write( "The blue group represents X because XY'+XY = X(Y'+Y) = X*1 = X
\n" ); document.write( "Similarly, the green group represents Y
\n" ); document.write( "X'Y+XY = (X'+X)Y = 1*Y = Y
\n" ); document.write( "Therefore, we end up with X+Y as the final simplification.\r
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\n" ); document.write( "\n" ); document.write( "Here's the boolean verification table
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XYX’X’YX+X’YX+Y
001000
011111
100011
110011

\n" ); document.write( "The last two columns for X+X'Y and X+Y are the same.
\n" ); document.write( "This proves that X+X'Y = X+Y\r
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\n" ); document.write( "\n" ); document.write( "Answer: X+Y
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