document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113019>Question 113019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> State method and factor completely<BR>\n" );
document.write( "2p-6q+pq-3q^\r<BR>\n" );
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document.write( "The method to be used is the grouping of terms but I am stuck on the factoring part because the 3q^ is not factorable if I'm not mistaken.  Can you assist me on understanding this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82318 by </B><A HREF=/tutors/aboutme.mpl?userid=SHUgrad05><B>SHUgrad05(58)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=SHUgrad05><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Should the problem read: 2p-6q+pq-3q^2???<BR>\n" );
document.write( "If so, group the first two terms and the last two terms then factor:\r<BR>\n" );
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document.write( "(2p-6q)+(pq-3q^2)<BR>\n" );
document.write( "2(p-3q)+q(p-3q)<BR>\n" );
document.write( "(2+q)(p-3q) </SPAN>\n" );
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