document.write( "Question 1191341: ABCD is an isosceles trapezoid (named counterclockwise) with median XY and diagonals AC and BD. If the measurement of angle DAB=2x-10 and the measurement of angle ADC is 3x+40, what is the measurement lf angle CBA \n" ); document.write( "

Algebra.Com's Answer #823161 by ikleyn(52786) $\"\"$ $\"About$

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document.write( "First,  angle A plus angle D is 180 degrees,  or\r\n" );
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document.write( "    (2x-10) + (3x + 40) = 180\r\n" );
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document.write( "           5x           = 180 + 10 - 40 = 150\r\n" );
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document.write( "            x           = 150/5 = 30,\r\n" );
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document.write( "Hence,  angle A is 2x-10 = 2*30-10 = 50  degrees.\r\n" );
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document.write( "Angle B (which is CBA) is congruent to angle A;  so, angle CBA is 50 degrees.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "The median XY is irrelevant to the problem.\r
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\n" ); document.write( "\n" ); document.write( "The diagonals AC and BD are irrelevant, too.\r
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