document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191322>Question 1191322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi this is the link of my question just copy the link and paste in the google or chrome thank you because i cant paste here the question<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823148 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20849)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Survival in the WILDERNESS\r<BR>\n" );
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document.write( "Each cell of the 10*10 map is equivalent to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.5km ALIGN=MIDDLE  ALT=\"0.5km\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "You need to avoid the cells showing dangers (like bandits, wild animals, etc). Your route must not touch those places.<BR>\n" );
document.write( "The blue thick line at the center of the map is a river. It is deep and the current is turbulent so swimming across it is out of the question. <BR>\n" );
document.write( "So the only way is to cross any of the bridges. The shorter route, the better!\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF=\"https://ibb.co/92LX50b\"><IMG STYLE=\"max-width:80%;\" src=\"https://i.ibb.co/92LX50b/Capture2-25-2022-3-47-21-PM.jpg\" alt=\"Capture2-25-2022-3-47-21-PM\" border=\"0\"></a>\r<BR>\n" );
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document.write( "from two right triangles with legs\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=6%2A0.5km=3km ALIGN=MIDDLE  ALT=\"a=6%2A0.5km=3km\"   DISABLED_style= \"max-width:90%; height:auto;\" >  (from “you” left under middle “bridge”)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=5.5%2A0.5km=2.75km ALIGN=MIDDLE  ALT=\"b=5.5%2A0.5km=2.75km\"   DISABLED_style= \"max-width:90%; height:auto;\" >  (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5.5 ALIGN=MIDDLE  ALT=\"5.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > units up to middle “bridge”)<BR>\n" );
document.write( "then hypothenuse is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=sqrt%283%5E2%2B2.75%5E2%29=4.1km ALIGN=MIDDLE  ALT=\"c=sqrt%283%5E2%2B2.75%5E2%29=4.1km\"   DISABLED_style= \"max-width:90%; height:auto;\" >-> distance from “you” to “bridge”\r<BR>\n" );
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document.write( "and, second right triangle is<BR>\n" );
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document.write( " go <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3+ ALIGN=MIDDLE  ALT=\"3+\"   DISABLED_style= \"max-width:90%; height:auto;\" >units up-><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=3km ALIGN=MIDDLE  ALT=\"a=3km\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3 ALIGN=MIDDLE  ALT=\"3\"   DISABLED_style= \"max-width:90%; height:auto;\" > units left -><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=3km ALIGN=MIDDLE  ALT=\"b=3km\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=sqrt%283%5E2%2B3%5E2%29=4.2km ALIGN=MIDDLE  ALT=\"c=sqrt%283%5E2%2B3%5E2%29=4.2km\"   DISABLED_style= \"max-width:90%; height:auto;\" > -> distance from the “bridge” to “safe place”\r<BR>\n" );
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document.write( "since diagonals are the shorter route, add both distances:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4.1km%2B4.2km=8.3km ALIGN=MIDDLE  ALT=\"+4.1km%2B4.2km=8.3km\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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