document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191313>Question 1191313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a class of 10 students 4 are girls 3 are selected at random.find the probability<BR>\n" );
document.write( "(a) 2 girls are selected<BR>\n" );
document.write( "(b) atleast 2 boys are selected<BR>\n" );
document.write( "(c) atmost 2 girls are selected </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823133 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10C3=120 ways to choose<BR>\n" );
document.write( "2 girls and 1 boy: numerator is 6C1*4C2=6*6=36, so probability is 0.3<BR>\n" );
document.write( "at least 2 boys are selected. For 2: 6C2*4C1=60 ways or 0.5 prob.<BR>\n" );
document.write( "3 boys would have 6C3*4C0 ways or 20 , so probability is 0.67 for at least 2<BR>\n" );
document.write( "at most 2 girls are selected are 2 boys 1 girl (0.5 prob. as stated above)<BR>\n" );
document.write( "the last (not asked for is) 3 girls and that is 4 ways or (0.0333 prob.<BR>\n" );
document.write( "----<BR>\n" );
document.write( "prob. 0 boys is 4/120<BR>\n" );
document.write( "1 boy is 36/120<BR>\n" );
document.write( "2 boys is 60/120<BR>\n" );
document.write( "3 boys is 20/120<BR>\n" );
document.write( "They add to 1.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );