document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191247>Question 1191247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> By adding the same constant to each of the numbers 16, 32, and 56, respectively, a geometric sequence is formed. What is the common ratio for this sequence? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #823065 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=823065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> add x<BR>\n" );
document.write( "(32+x)/(16+x)=(56+x)/(32+x), since the ratios are the same between adjacent numbers.<BR>\n" );
document.write( "1024+64x+x^2=896+72x+x^2<BR>\n" );
document.write( "128=8x<BR>\n" );
document.write( "x=16<BR>\n" );
document.write( "so the geometric sequence is 32, 48, 72, and the ratio is 1.5 </SPAN>\n" );
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