document.write( "Question 1191180: x + y + z =6
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document.write( "x+2y+3z=10
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document.write( "x+2y+az=b) \n" );
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Algebra.Com's Answer #822975 by ikleyn(52810)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " This post came with no question, which makes me very sad \r \n" ); document.write( "\n" ); document.write( " (as usual as I see such an inaccuracy and disrespect to the tutors).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " The short resume to this problem is as follows.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(1) The case a= 3 is special.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " If a= 3 and b= 10, then there are infinitely many solutions.\r\n" ); document.write( "\r\n" ); document.write( " In this case, the system is dependent.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " If a= 3 and b =/= 10, then there is NO solutions and the system is inconsistent.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(2) If a =/= 3, then we have three independent equations;\r\n" ); document.write( "\r\n" ); document.write( " the system is consistent and has a unique solution.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Answered.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |