document.write( "Question 1191175: 2. In how many orders can 7 different pictures be hung in a row so that 1 specified picture is
\n" ); document.write( "(a) at the center,
\n" ); document.write( "(b) at either end?\r
\n" ); document.write( "\n" ); document.write( "Show full solution, thank you! \n" ); document.write( "

Algebra.Com's Answer #822964 by ikleyn(52814) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "(a)  One of the 7 pictures is fixed;  6 other can be arranged in any order in the remaining 6 positions.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "     The answer is 6! = 6*5*4*3*2*1 = 720 possible permutations.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(b)  6! + 6! = 720 + 720 = 1440 possible permutations / arrangements.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "     First   720 arrangements with the specified picture at the left end, and\r\n" );
document.write( "\r\n" );
document.write( "     another 720 arrangements with the specified picture at the right end.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved, answered and explained.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );