document.write( "Question 1191119: Find the equation of the hyperbola for each given condition.\r
\n" ); document.write( "\n" ); document.write( "c. Center at (-2, 2); a focus at (6, 2); and a vertex at (4,2)
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Algebra.Com's Answer #822934 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "given: \r
\n" ); document.write( "\n" ); document.write( "Center at (\"-2\",\"2\")=>\"h=-2\", \"k=2\"\r
\n" ); document.write( "\n" ); document.write( "a focus at (\"6\",\"2\")=> focus is (\"h+-+c\", \"k+\") = (\"6\",\"2\")=>\"-2+-+c=6\"=>\"-2-6=c\"=>\"c=-8\"\r
\n" ); document.write( "\n" ); document.write( "a vertex at (\"4\",2).=> (\"h+%2B+a\", \"k\") = (\"4\", \"2\")=>\"-2+%2B+a=4\"=>\"a=2%2B4\"=>\"a=6\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=c%5E2-a%5E2\"
\n" ); document.write( "\"b%5E2=%28-8%29%5E2-6%5E2\"
\n" ); document.write( "\"b%5E2=64-36\"
\n" ); document.write( "\"b%5E2=28\"\r
\n" ); document.write( "\n" ); document.write( "equation is:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-%28-2%29%29%5E2%2F6%5E2-%28y-2%29%5E2%2F28=1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2%2F36-%28y-2%29%5E2%2F28=1\"\r
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