document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191159>Question 1191159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what are the last two digits of the number <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+7%5E8910+ ALIGN=MIDDLE  ALT=\"+7%5E8910+\"   DISABLED_style= \"max-width:90%; height:auto;\" > when it is fully calculated out? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822931 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The sequence of the last two digits of increasing powers of 7 will form a repeating pattern.  Use the length of that pattern to find the answer.<br><BR>\n" );
document.write( "07<BR>\n" );
document.write( "49<BR>\n" );
document.write( "43<BR>\n" );
document.write( "01<BR>\n" );
document.write( "07<BR>\n" );
document.write( "....<br><BR>\n" );
document.write( "That is a very short pattern with length 4.<br><BR>\n" );
document.write( "The exponent 8910, divided by 4, leaves remainder 2, so the answer is the 2nd number in the repeating pattern: 49<br><BR>\n" );
document.write( "ANSWER: 49<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );