document.write( "Question 1191153: Given g(x)= -12x-5
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Algebra.Com's Answer #822917 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Given $\"g%28x%29=+-12x-5\"$ \r
\n" ); document.write( "\n" ); document.write( "Find $\"g%5E-1%28-5%29\"$ \r
\n" ); document.write( "\n" ); document.write( "first find $\"g%5E-1%28x%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"g%28x%29=+y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=+-12x-5\"$ .....swap variables\r
\n" ); document.write( "\n" ); document.write( " $\"x=+-12y-5\"$ ......solve for $\"+y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"12y=+-x-5\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=+%28-x-5%29%2F12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"g%5E-1%28x%29=+%28-x-5%29%2F12\"$ .......substitute $\"-5\"$ for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"g%5E-1%28-5%29=+%28-%28-5%29-5%29%2F12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"g%5E-1%28-5%29=+%285-5%29%2F12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"g%5E-1%28-5%29=+0%2F12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"g%5E-1%28-5%29=+0\"$ \r
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