document.write( "Question 1191120: Hello, I have an assignment I've been scratching my head about.\r
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document.write( "Person A sends messages every 16 minutes, Person B - every 16 minutes, Person C - every 14 minutes. What is the probability of receiving at least ONE message in the span of 6 minutes? JUST ONE message in the span of 6 minutes? And JUST TWO messages in the span of 6 minutes? \n" );
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Algebra.Com's Answer #822902 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "From the given conditions.... \n" ); document.write( "P(A sends a message in a span of 6 minutes) = 6/16 = 3/8 \n" ); document.write( "P(A does not send a message in a span of 6 minutes) = 5/8 \n" ); document.write( "P(B sends a message in a span of 6 minutes) = 6/16 = 3/8 \n" ); document.write( "P(B does not send a message in a span of 6 minutes) = 5/8 \n" ); document.write( "P(C sends a message in a span of 6 minutes) = 6/14 = 3/7 \n" ); document.write( "P(A does not send a message in a span of 6 minutes) = 4/7 \n" ); document.write( "Then.... \n" ); document.write( "P(only A sends a message in a span of 6 minutes) = (3/8)(5/8)(4/7) = 60/448 \n" ); document.write( "P(only B sends a message in a span of 6 minutes) = (5/8)(3/8)(4/7) = 60/448 \n" ); document.write( "P(only C sends a message in a span of 6 minutes) = (5/8)(5/8)(3/7) = 75/448 \n" ); document.write( "ANSWER #1: P(receiving only 1 message in a span of 6 minutes) = 195/448 \n" ); document.write( "P(A and B send a message in a span of 6 minutes) = (3/8)(3/8)(4/7) = 36/448 \n" ); document.write( "P(A and C send a message in a span of 6 minutes) = (3/8)(5/8)(3/7) = 45/448 \n" ); document.write( "P(B and D send a message in a span of 6 minutes) = (5/8)(3/8)(3/7) = 45/448 \n" ); document.write( "ANSWER #2: P(receiving two messages in a span of 6 minutes) = 126/448 \n" ); document.write( "Simplify the fraction answers or convert to decimals or percentages as required/desired. \n" ); document.write( " \n" ); document.write( " |