document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191116>Question 1191116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "A phone company charges 35c for the first minute of a call and 15c for each additional minute of the call. What is the cost y of a phone call lasting x minutes. \r<BR>\n" );
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document.write( "Thanks <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822877 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the function would be y = .20 + .15 * x\r<BR>\n" );
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document.write( "the value of x is determined by the duration of the call.\r<BR>\n" );
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document.write( "if the call lasts less than or equal to 1 minute, then x = 1 and the formula becomes y = .20 + .15 * 1 = .35\r<BR>\n" );
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document.write( "if the call lasts more than 1 minute and less than or equal to 2 minutes, then x = 2 and y = .20 + .15 * 2 = .50\r<BR>\n" );
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document.write( "if the call lasts more than 2 minutes and less than or equal to 3 minutes, then x = 3 and y = .20 + .15 * 3 = .65\r<BR>\n" );
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document.write( "if the call lasts more than 3 minutes and less than or equal to 4 minutes, then x = 4 and y = .20 + .15 * 4 = .80.\r<BR>\n" );
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document.write( "if the call lasts more than 4 minutes but less than or equal to 5 minutes, than x = 5 and y = .35 + .15 * 4.= = .95\r<BR>\n" );
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document.write( "the function can be graphed.\r<BR>\n" );
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document.write( "it looks like this.\r<BR>\n" );
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