document.write( "Question 1191089: Find the equation of the hyperbola for each given conditions.\r
\n" ); document.write( "\n" ); document.write( "a. Vertices at (o,3) and (0,-3) and a focus at (0,5).
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Algebra.Com's Answer #822870 by MathLover1(20850)\"\" \"About 
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\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "given: \r
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\n" ); document.write( "\n" ); document.write( " Vertices at (\"0\",\"3\") and (\"0\",\"-3\")
\n" ); document.write( "a focus at (\"0\",\"5\")
\n" ); document.write( "in your case the transverse axis lies on the y-axis, the vertices are located at (\"0\"\"a\"), and the foci are located at (\"0\"\"c\")
\n" ); document.write( "=>\"a=3\"
\n" ); document.write( "=> \"c=5\"
\n" ); document.write( "Center is half way between, at (\"0\",\"0\")=>\"h=0\", \"k=0\"\r
\n" ); document.write( "\n" ); document.write( "in this case your equation is of the form:\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2Fa%5E2-x%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( " find \"a\" can be found using this formula:\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2+=+c%5E2+-+a%5E2\"
\n" ); document.write( "\"b%5E2+=+25+-+9\"
\n" ); document.write( "\"b%5E2+=+16\"
\n" ); document.write( "\"b=4+\"\r
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\n" ); document.write( "\n" ); document.write( "equation is:\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2F9-x%5E2%2F16=1\"\r
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