document.write( "Question 1190874: Loraine is eighteen years older than her cousin. She was three times as old one year ago.
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Algebra.Com's Answer #822867 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Loraine is eighteen years older than her cousin. She was three times as old one year ago.
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Difference in ages will ALWAYS be 18, with Loraine being older\r\n" );
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document.write( "Let the cousin's age be C\r\n" );
document.write( "Then Loraine's is C + 18\r\n" );
document.write( "We then get: C + 18 - 1 = 3(C - 1)\r\n" );
document.write( "                 C + 17 = 3C - 3\r\n" );
document.write( "                 C - 3C = - 3 - 17\r\n" );
document.write( "                   - 2C = - 20\r\n" );
document.write( "The cousin's age, or \r\n" );
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document.write( "You should now be able to find Loraine's age.
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