document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191083>Question 1191083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> he body temperatures in degrees Fahrenheit of a sample of adults in one small town are:<BR>\n" );
document.write( "97.9	99.8	98.2	97.3	97.4	98.1	97.7	96.9	99.7	99.9	99.6\r<BR>\n" );
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document.write( "Assume body temperatures of adults are normally distributed. Based on this data, find the 99% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population.\r<BR>\n" );
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document.write( "99% C.I.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822851 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean is 98.409<BR>\n" );
document.write( "s=1.126<BR>\n" );
document.write( "99% CI half-interval is t (0.995,df=10)*s/sqrt(n)=3.169*1.126/sqrt(11)=1.076<BR>\n" );
document.write( "interval is mean+/- half-interval  or (97.333 deg, 99.485 deg) </SPAN>\n" );
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