document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191077>Question 1191077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Normally a factory produces 400 radios in x days. IF the factory were to produce 20 more radios each day, then it would take 10 days less to produce 400 radios. find x  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822845 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor has provided a good detailed response showing a formal algebraic solution.<br><BR>\n" );
document.write( "If a formal algebraic solution is not required, you can find it quickly with a bit of mental arithmetic.<br><BR>\n" );
document.write( "The conditions of the problem require you to find two ways to expression 400 as the product of two numbers...<br><BR>\n" );
document.write( "ab=400<BR>\n" );
document.write( "cd=400<br><BR>\n" );
document.write( "... in which the difference between a and c (the numbers of radios produced per day) is 20 and the difference between b and d (the number of days) is 10.<br><BR>\n" );
document.write( "Quick trial and error should easily find<br><BR>\n" );
document.write( "20*20=400<BR>\n" );
document.write( "40*10=400<br><BR>\n" );
document.write( "Those show that 400 radios can be produced 20 per day for 20 days, or 40 per day for 10 days.  Those numbers satisfy the conditions of the problem: producing 20 more per day requires 10 fewer days.<br><BR>\n" );
document.write( "ANSWER: 20<br><BR>\n" );
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