document.write( "Question 1191041: if f (1) = 6 and f (n)= f (n-1) + 2 then find the value of f (4) \n" ); document.write( "
Algebra.Com's Answer #822787 by MathLover1(20849)\"\" \"About 
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Let the place count be \"n\"
\n" ); document.write( "Let the \"n\"th term be \"a%5Bn%5D\"\r
\n" ); document.write( "\n" ); document.write( "Given \"f%28n=1%29=6\"\r
\n" ); document.write( "\n" ); document.write( "We are also told that any one term is the previous term + \"2\".\r
\n" ); document.write( "\n" ); document.write( "This is derived from \"f%28n%29=f%28n-1%29%2B2\" where \"f%28n-1%29+\"is the previous term.\r
\n" ); document.write( "\n" ); document.write( "Consequently we have an Arithmetic sequence with common difference of +\"2\"\r
\n" ); document.write( "\n" ); document.write( "From this the sequence is:\r
\n" ); document.write( "\n" ); document.write( "\"n=1\"\"a%5B1%5D=6\"← given value\r
\n" ); document.write( "\n" ); document.write( "\"n=2\"\"a%5B2%5D=6%2B2=8\"
\n" ); document.write( "\"n=3\"\"a%5B3%5D=6%2B2%2B2=10\"
\n" ); document.write( "\"highlight%28n=4%29\"\"highlight%28a%5B4%5D=6%2B2%2B2%2B2=12%29\"\r
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\n" ); document.write( "\n" ); document.write( "so, the value of \"highlight%28f%284%29%29\" is \"highlight%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "And so on. Also from this we also have an alternative equation for any an in that we have:\r
\n" ); document.write( "\n" ); document.write( "\"a%5Bn%5D=6%2B2%28n-1%29\"\r
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