document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1191010>Question 1191010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822768 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13367)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822768\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The equation of any line perpendicular to the line 4x-5y=-10 will have the form 5x+4y=C for some constant C.  Note that to get that form, the two coefficients are switched, and the sign is changed.<br><BR>\n" );
document.write( "To get the equation you want, simply substitute the given values x=6 and y=3 to find the value of C.<br><BR>\n" );
document.write( "5x+4y = 5(6)+4(3) = 30+12 = 42<br><BR>\n" );
document.write( "ANSWER: 5x+4y=42<br><BR>\n" );
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