document.write( "Question 1190937: what is the mean and standard deviation of the sampling distribution of proportions respectively, given that n=100 and p= 0.5 \n" ); document.write( "
Algebra.Com's Answer #822689 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "p = 0.5 is the population proportion \n" ); document.write( "Each various sample proportion is denoted as \n" ); document.write( "The symbol \n" ); document.write( "The \"ph\" isn't sounded out as an \"f\" sound. The \"p\" is separate from the \"hat\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sample distribution consists of random phat values based on repeated samplings of the population. \n" ); document.write( "In this case, we're sampling 100 individuals to compute the phat values.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The phat distribution will have a mean of p = 0.5 because the phat values will fall on either side of this center. The more data points, the better the picture will come into focus that the center is 0.5 \n" ); document.write( "This is all due to the fact the sampling distribution is clustered around the population parameter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The standard deviation for the phat values isn't as simple unfortunately. \n" ); document.write( "The good news is that the formula isn't too crazy. \n" ); document.write( "sigma = sqrt(p*(1-p)/n) \n" ); document.write( "sigma = sqrt(0.5*(1-0.5)/100) \n" ); document.write( "sigma = sqrt(0.5*0.5/100) \n" ); document.write( "sigma = sqrt(0.25/100) \n" ); document.write( "sigma = sqrt(0.0025) \n" ); document.write( "sigma = 0.05\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's where you can find more info \n" ); document.write( "https://online.stat.psu.edu/stat500/lesson/4/4.2/4.2.2 \n" ); document.write( "and here's a page with a similar example problem to get more practice \n" ); document.write( "https://www.khanacademy.org/math/ap-statistics/sampling-distribution-ap/sampling-distribution-proportion/e/sampling-distribution-sample-proportion-mean-standard-deviation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answers: \n" ); document.write( "mean = 0.5 \n" ); document.write( "standard deviation = 0.05 \n" ); document.write( " \n" ); document.write( " |