document.write( "Question 1190935: Find the coordinates of the points on the curve y = x^2/(2x-1) where dy/dx = 0. \n" ); document.write( "
Algebra.Com's Answer #822683 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Find the coordinates of the points on the curve y = x^2/(2x-1) where dy/dx = 0.
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\n" ); document.write( "\n" ); document.write( "            In this problem, there are TWO points, satisfying the condition dy/dx=0.\r
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\n" ); document.write( "\n" ); document.write( "            @josgarithmetic found one point and missed another.\r
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\n" ); document.write( "\n" ); document.write( "            I came to bring full correct solution.\r
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document.write( "\"%28dy%29%2F%28dx%29\" = ((2x-1)(x^2)'-x^2(2x-1)')/(2x-1)^2\r\n" );
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document.write( "\"%28dy%29%2F%28dx%29\" = \"%282x%2A%282x-1%29-2x%5E2%29%2F%282x-1%29%5E2\"\r\n" );
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document.write( "\"%28dy%29%2F%28dx%29\" = \"%282x%5E2-2x%29%2F%282x-1%29%5E2\"\r\n" );
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document.write( "\"%28dy%29%2F%28dx%29\" = \"%282x%28x-1%29%29%2F%282x-1%29%5E2\"\r\n" );
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document.write( "\"dy%2Fdx\" = 0   has two solutions  x= 0  and  x= 1.\r\n" );
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document.write( "The two points on the curve with zero derivative are  (x,y) = (0,0)  and  (x,y) = (1,1).      ANSWER\r\n" );
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document.write( "               Visual illustration\r\n" );
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document.write( "    \r\n" );
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document.write( "    Plot  y = \"x%5E2%2F%282x-1%29\"  (red)  and  y= 1  (horizontal tangent, green)\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved (correctly).\r
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