document.write( "Question 1190935: Find the coordinates of the points on the curve y = x^2/(2x-1) where dy/dx = 0. \n" ); document.write( "
Algebra.Com's Answer #822680 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
dy/dx=((2x-1)(x^2)'-x^2(2x-1)')/(2x-1)^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"dy%2Fdx=%282x%282x-1%29-2x%5E2%29%2F%282x-1%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"dy%2Fdx=%282x%5E2-2x%29%2F%282x-1%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"dy%2Fdx=0=2x%5E2-2x\" \"only\"\"need\"\"numerator\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"system%28for%2Cx=0%2C+and%2C+cross%28x=1%29%29\"\r
\n" ); document.write( "\n" ); document.write( "point (0,0)
\n" ); document.write( "
\n" );