document.write( "Question 112934: Please help me find a general term a sub n for the sequence 1/3, 2/4, 3/5, 4/6,... \n" ); document.write( "
Algebra.Com's Answer #82266 by jim_thompson5910(35256)\"\" \"About 
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Looking at the sequence of the numerators, we see: 1,2,3,4,...\r
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\n" ); document.write( "\n" ); document.write( "And we can see that the numerators are increasing by 1 each time and start at 1. So if we start at n=0, then the general sequence for the numerators is: \"n%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the sequence of the denominators, we see: 3,4,5,6,...\r
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\n" ); document.write( "\n" ); document.write( "And we can see that the denominators are increasing by 1 each time, but are starting at 3. So if we start at n=0, then the general sequence for the denominators is: \"n%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "So putting this all together we get\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%2B1%29%2F%28n%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we let n=0, we get\r
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\n" ); document.write( "\n" ); document.write( "\"%280%2B1%29%2F%280%2B3%29=1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "If we let n=1, we get\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2B1%29%2F%281%2B3%29=2%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "If we let n=2, we get\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2B1%29%2F%282%2B3%29=3%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "And finally, if we let n=3, we get\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2B1%29%2F%283%2B3%29=4%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "So this verifies our answer.
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