document.write( "Question 1190910: Given the function f(x)=8-x^3, x>_0 (line goes under >)
\n" ); document.write( "a) Sketch the graph of f (use a solid line, label f(x)
\n" ); document.write( "b) Use the graph of f above and sketch the graph of f^-1 on the same axis as in part a) of this problem (use a dashed line, label the inverse). How did you find the points to sketch the inverse function?
\n" ); document.write( "c) Find f^-1(x)
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Algebra.Com's Answer #822644 by Boreal(15235)\"\" \"About 
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f(x)=8-x^3
\n" ); document.write( "inverse
\n" ); document.write( "x=8-y^3
\n" ); document.write( "y^3=8-x
\n" ); document.write( "y=(8-x)^(1/3)
\n" ); document.write( "\"graph%28300%2C300%2C0%2C10%2C-10%2C10%2C8-x%5E3%2C%288-x%29%5E%281%2F3%29%29\"
\n" ); document.write( "To find the points for the inverse, (8, 0) is one, and (0, 2) is the other. The two are equal when
\n" ); document.write( "8-x^3=(8-x)^(1/3)
\n" ); document.write( "One way is to graph both and find where they intersect, which is at x=1.834.
\n" ); document.write( "One can put in points for x and take the cube root.
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