document.write( "Question 1190910: Given the function f(x)=8-x^3, x>_0 (line goes under >)
\n" );
document.write( "a) Sketch the graph of f (use a solid line, label f(x)
\n" );
document.write( "b) Use the graph of f above and sketch the graph of f^-1 on the same axis as in part a) of this problem (use a dashed line, label the inverse). How did you find the points to sketch the inverse function?
\n" );
document.write( "c) Find f^-1(x) \n" );
document.write( "
Algebra.Com's Answer #822644 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! f(x)=8-x^3 \n" ); document.write( "inverse \n" ); document.write( "x=8-y^3 \n" ); document.write( "y^3=8-x \n" ); document.write( "y=(8-x)^(1/3) \n" ); document.write( " \n" ); document.write( "To find the points for the inverse, (8, 0) is one, and (0, 2) is the other. The two are equal when \n" ); document.write( "8-x^3=(8-x)^(1/3) \n" ); document.write( "One way is to graph both and find where they intersect, which is at x=1.834. \n" ); document.write( "One can put in points for x and take the cube root. \n" ); document.write( " \n" ); document.write( " |