document.write( "Question 1190899: I need your help with this!
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Algebra.Com's Answer #822638 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "I need your help with this!
\n" ); document.write( "Assume Pr[A]=0.3, Pr[B]=0.4, and Pr[A∩B]=0.05. Find the following values:
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\n" ); document.write( "\n" ); document.write( "            In this problem,  all questions ask about  CONDITIONAL  PROBABILITY.\r
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\n" ); document.write( "\n" ); document.write( "            To solve the problem and to answer all the questions,  you need firmly know  WHAT  the conditional probability is.\r
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\n" ); document.write( "\n" ); document.write( "            If  X  and  Y are the events in the universal set of events,  then  P(X|Y)  is  THIS  ratio\r
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document.write( "                   P(X|Y) =  \"P%28X_and_Y%29%2FP%28Y%29\" .         \r\n" );
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document.write( "(a)  P(B|A) = \"P%28A_and_B%29%2FP%28A%29\" = \"0.05%2F0.3\" = \"5%2F30\" = \"1%2F6\".    ANSWER\r\n" );
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document.write( "     Solved.    So, it is easy.\r\n" );
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document.write( "(b)  P(A|B').\r\n" );
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document.write( "     We should find  P(A ∩ B').  The set  (A ∩ B') are those elements/(events) of A that do not belong to B.\r\n" );
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document.write( "     From it, it is clear that the set (A ∩ B') is  (A \ (A ∩ B)).  \r\n" );
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document.write( "     Therefore,  P(A ∩ B') = P(A) - P(A ∩ B) = 0.3 - 0.05 = 0.25.\r\n" );
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document.write( "     Next, P(B') = 1 - P(B) = 1 - 0.4 = 0.6.\r\n" );
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document.write( "     THEREFORE,  P(A|B') = \"0.25%2F0.6\" = \"25%2F60\" = \"5%2F12\".      ANSWER\r\n" );
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document.write( "(c)  P(A'|B').\r\n" );
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document.write( "     We should find  P(A' ∩ B').  The set  (A' ∩ B') are those elements/(events) of the universal set that belong NEITHER A NOR B.\r\n" );
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document.write( "     From it, it is clear that the set (A' ∩ B') is  the complement of (A U B).  \r\n" );
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document.write( "     P(A U B) = P(A) + P(B) - P(A ∩ B) = 0.3 + 0.4 - 0.05 = 0.65.\r\n" );
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document.write( "     Therefore,  P(A' ∩ B') = 1 - P(A U B) = 1 - 0.65 = 0.35.\r\n" );
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document.write( "     Next, P(B') = 1 - P(B) = 1 - 0.4 = 0.6.\r\n" );
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document.write( "     THEREFORE,  P(A'|B') = \"0.35%2F0.6\" = \"35%2F60\" = \"7%2F12\".      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "All questions are answered.\r
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