document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190897>Question 1190897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sam jogged to Larry's house at 8 miles per hour and borrowed Larry's scooter, riding back at 20 miles per hour. If the round trip took 7 hours, how far is it to Larry's house?  Write a distance equation  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822637 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Ignoring the \"write a distance equation\" instruction in your post, here is a fast and easy way to solve this kind of problem.<br><BR>\n" );
document.write( "The ratio of speeds for the two legs of the trip is 8:20 = 2:5.<br><BR>\n" );
document.write( "Since the distances for the two legs are the same, that means the ratio of times spent at the two speeds is 5:2.<br><BR>\n" );
document.write( "Since the total time was 7 hours and the ratio of times on the two legs is 5:2, he spent 5 hours jogging and 2 hours riding.<br><BR>\n" );
document.write( "So the distance on each leg is 5*8=40 miles, or 2*20=40 miles.<br><BR>\n" );
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