document.write( "Question 1190875: Four years ago, Noriel was three less than twice King’s age. In five years, Noriel will be 6
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Algebra.Com's Answer #822635 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let x = King's age 4 years ago
\n" ); document.write( "Then 2x-3 = Noriel's age 4 years ago

\n" ); document.write( "Since Noriel will be 6 years older than King 5 years from now, the difference in their ages is (always) 6:

\n" ); document.write( "\"%282x-3%29-x=6\"
\n" ); document.write( "\"x-3=6\"
\n" ); document.write( "\"x=9\"

\n" ); document.write( "4 years ago, their ages were x=9 and 2x-3=15.

\n" ); document.write( "ANSWERS: Their ages now are 9+4=13 and 15+4=19

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