document.write( "Question 1190874: Loraine is eighteen years older than her cousin. She was three times as old one year ago.
\n" ); document.write( "How old are they now?
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Algebra.Com's Answer #822611 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "c = cousin's current age
\n" ); document.write( "c+18 = Loraine's current age, since she is 18 years older.\r
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\n" ); document.write( "\n" ); document.write( "Rewinding the clock 1 year ago, we have these past ages
\n" ); document.write( "c-1 = cousin's past age
\n" ); document.write( "(c+18)-1 = c+17 = Loraine's past age\r
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\n" ); document.write( "\n" ); document.write( "Last year she was 3 times as old as her cousin, so,
\n" ); document.write( "her past age = 3*(cousin's past age)
\n" ); document.write( "c+17 = 3*(c-1)
\n" ); document.write( "c+17 = 3c-3
\n" ); document.write( "17+3 = 3c-c
\n" ); document.write( "20 = 2c
\n" ); document.write( "2c = 20
\n" ); document.write( "c = 20/2
\n" ); document.write( "c = 10\r
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\n" ); document.write( "\n" ); document.write( "Her cousin is currently 10 years old.
\n" ); document.write( "Loraine is currently c+18 = 10+18 = 28 years old.\r
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\n" ); document.write( "\n" ); document.write( "One year ago, her cousin was 10-1 = 9 years old and Loraine was 28-1 = 27 years old.
\n" ); document.write( "The jump from 9 to 27 is \"times 3\" to help fully confirm we have the correct ages.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "Loraine is currently 28 years old
\n" ); document.write( "Her cousin is currently 10 years old
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