document.write( "Question 1190852: the outside of a picture frame has a length which is 5cm more than the width, the area enclosed of the picture frame is 126cm what is the width of the outside \n" ); document.write( "
Algebra.Com's Answer #822581 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "the outside of a picture frame has a length which is 5cm more than the width,
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document.write( "    w*(w+5) = 126\r\n" );
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document.write( "    w^2 + 5w - 126 = 0\r\n" );
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document.write( "    \"w%5B1%2C2%5D\" = \"%28-5+%2B-+sqrt%285%5E2+-4%2A1%2A%28-126%29%29%29%2F2\" = \"%28-5+%2B-+sqrt%28529%29%29%2F2\" = \"%28-5%2B-+23%29%2F2\".\r\n" );
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document.write( "We discard the negative root and accept the positive one.\r\n" );
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document.write( "ANSWER.  The width is  \"%28-5+%2B+23%29%2F2\" = 9 cm.\r\n" );
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