document.write( "Question 1190831: the diagonal of a rectangle is 6cm longer than its base. Its height is 10 cm more than one-third of its base. Find the dimension of the resctangle. \n" ); document.write( "
Algebra.Com's Answer #822559 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "Let b=base
\n" ); document.write( "Let h=height
\n" ); document.write( "Let d=diagonal\r
\n" ); document.write( "\n" ); document.write( "Given:
\n" ); document.write( "d = b+6
\n" ); document.write( "h = (b/3)+10\r
\n" ); document.write( "\n" ); document.write( "By Pythagorean theorem:
\n" ); document.write( "\"d%5E2+=+b%5E2+%2B+h%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "Substitute the givens to get one eqn w/one unknown:
\n" ); document.write( "\"+%28b%2B6%29%5E2+=+b%5E2+%2B+%28%28b%2F3%29%2B10%29%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "Expand (and cancel one \"b%5E2\" from each side):
\n" ); document.write( "\"+cross%28b%5E2%29+%2B+12b%2B36+=+cross%28b%5E2%29+%2B+b%5E2%2F9+%2B+20b%2F3+%2B+100+\"\r
\n" ); document.write( "\n" ); document.write( "Multiply both sides by 9:
\n" ); document.write( "\"+108b%2B324+=+b%5E2%2B60b%2B900+\"\r
\n" ); document.write( "\n" ); document.write( "Bring it all over to one side:
\n" ); document.write( "\"+b%5E2+-48b+%2B576+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "\"+%28b-24%29%5E2+=+0+\" ---> b = 24 --> h = 18, d = 30\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"d%5E2\" = \"30%5E2+\" = 900
\n" ); document.write( "\"+b%5E2+%2B+h%5E2+=+24%5E2+%2B+18%5E2+=+576+%2B+324+=+900+\" (ok!)\r
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