document.write( "Question 1190827: The sum of a number and twice its reciprocal is 51/5. What is the number?
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Algebra.Com's Answer #822552 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let the number be x; then twice the reciprocal is 2/x.

\n" ); document.write( "The sum of the two s 51/5:

\n" ); document.write( "\"x%2B2%2Fx=51%2F5\"

\n" ); document.write( "Multiply everything by the least common denominator 5x to clear fractions:

\n" ); document.write( "\"5x%5E2%2B10=51x\"
\n" ); document.write( "\"5x%5E2-51x%2B10=0\"
\n" ); document.write( "\"%285x-1%29%28x-10%29=0\"
\n" ); document.write( "\"x=1%2F5\" or \"x=10\"

\n" ); document.write( "ANSWER: The two numbers are 1/5 and 10

\n" ); document.write( "CHECK:
\n" ); document.write( "x=1/5 --> 2/x=10 --> x+2/x=10+1/5=51/5
\n" ); document.write( "x=10 --> 2/x=1/5 --> x+2/x=10+1/5=51/5

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