document.write( "Question 112883: Please help solve this problem for me I am having a hard time my instructor is not making it easy. Thank you
\n" ); document.write( " Solve 2x^-3x-2=0 using quadratic formula. show detail work. Thank you again
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Algebra.Com's Answer #82255 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"2%2Ax%5E2-3%2Ax-2=0\" ( notice \"a=2\", \"b=-3\", and \"c=-2\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28--3+%2B-+sqrt%28+%28-3%29%5E2-4%2A2%2A-2+%29%29%2F%282%2A2%29\" Plug in a=2, b=-3, and c=-2\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%2A2%2A-2+%29%29%2F%282%2A2%29\" Negate -3 to get 3\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9-4%2A2%2A-2+%29%29%2F%282%2A2%29\" Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because \"%28-3%29%5E2=-3%2A-3=9\".)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9%2B16+%29%29%2F%282%2A2%29\" Multiply \"-4%2A-2%2A2\" to get \"16\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+25+%29%29%2F%282%2A2%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+5%29%2F%282%2A2%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+5%29%2F4\" Multiply 2 and 2 to get 4\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B+5%29%2F4\" or \"x+=+%283+-+5%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%283+%2B+5%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=8%2F4\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%283+-+5%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2F4\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-1%2F2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=-1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=-1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"2%2Ax%5E2-3%2Ax-2\", we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-11%2C+12%2C+-11%2C+12%2C2%2Ax%5E2%2B-3%2Ax%2B-2%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the roots are \"x=2\" and \"x=-1%2F2\". This verifies our answer
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