document.write( "Question 1190822: A man invested part of P10, 000 at 6% and the rest at 7%. The annual income from the 7% investment was P35 less than seven times the annual income from the 6 % investment. How much did he invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #822544 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "A man invested part of P10, 000 at 6% and the rest at 7%.
\n" ); document.write( "The annual income from the 7% investment was P35 less than seven times
\n" ); document.write( "the annual income from the 6 % investment. How much did he invest at each rate?
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document.write( "Let x be invested at 7%;  then the rest,  (10000-x) is invested at 6%.\r\n" );
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document.write( "The annual interest of the 7% investment is  0.07x.\r\n" );
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document.write( "The annual interest of the 6% investment is  0.06*(10000-x).\r\n" );
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document.write( "The problem says that\r\n" );
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document.write( "    0.07x = 7*0.06*(10000-x) - 35.\r\n" );
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document.write( "From this equation\r\n" );
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document.write( "    x =  = 8500.\r\n" );
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document.write( "ANSWER.  P 8500 invested at 7% and the rest, 10000-8500 = 1500 invested at 6%.\r\n" );
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document.write( "CHECK.   0.07*8500 = 595;   0.06*1500 = 90;   7*90 - 595 = 630 - 595 = 35,  the difference.    ! Correct !\r\n" );
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