document.write( "Question 1190798: Find the equation of the parabola with vertex on the line y = 2, axis parallel to Oy, latus rectum 6, and passing through (2, 8). \n" ); document.write( "
Algebra.Com's Answer #822543 by MathLover1(20849)\"\" \"About 
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the equation of the parabola with latus rectum \"+6\"
\n" ); document.write( "length of latus rectum is \"+6\", so the leading coefficient is ±\"1%2F6\"
\n" ); document.write( "vertex on the line \"y+=+2\"=>\"k=2\"\r
\n" ); document.write( "\n" ); document.write( "so far we have:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%281%2F6%29%28x-h%29%5E2%2B2\"\r
\n" ); document.write( "\n" ); document.write( "passing through (\"2\", \"8\")\r
\n" ); document.write( "\n" ); document.write( "use it to calculate \"h\" \r
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\n" ); document.write( "\n" ); document.write( "\"8+=+%281%2F6%29%282-h%29%5E2%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"8+=+h%5E2%2F6+-+%282+h%29%2F3+%2B+8%2F3\" .......multiply by common denominator \"6\"\r
\n" ); document.write( "\n" ); document.write( "\"48+=+h%5E2+-+4+h+%2B+16\"\r
\n" ); document.write( "\n" ); document.write( "\"+h%5E2+-+4+h+%2B+16-48=0\"\r
\n" ); document.write( "\n" ); document.write( "\"+h%5E2+-+4+h+-32=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28h+%2B+4%29+%28h+-+8%29=0\"\r
\n" ); document.write( "\n" ); document.write( "=>\"h=-4\" or \"h=8\"\r
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\n" ); document.write( "\n" ); document.write( "and, your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%281%2F6%29%28x%2B4%29%5E2%2B2\"
\n" ); document.write( "or
\n" ); document.write( "\"y+=+%281%2F6%29%28x-8%29%5E2%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "graph: \"y+=+%281%2F6%29%28x%2B4%29%5E2%2B2\"\r
\n" ); document.write( "\n" ); document.write( " \r
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\n" ); document.write( "\n" ); document.write( "graph: \"y+=+%281%2F6%29%28x-8%29%5E2%2B2\"\r
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