document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190772>Question 1190772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 2014, TTEC had the following rate schedule for electricity usage for residential purposes; <BR>\n" );
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document.write( "Monthly service charge $200.00 Per KWh charge: <BR>\n" );
document.write( "1st 600 KWh:  $1.25/KWh <BR>\n" );
document.write( "Over 600 KWh: $2.51/KWh <BR>\n" );
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document.write( "(i)	What is the charge for using 599 KWh in a month?  	 	 	 	 	[2] <BR>\n" );
document.write( "(ii)	What is the charge for using 2600 KWh in a month? 	 	 	 	 	[3] <BR>\n" );
document.write( "(iii)	If C is the monthly charge for x KWh, develop a model relating the monthly charge and kilowatt-hours used. That is, express C as a function of x.     [4] <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822514 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i understand this as:\r<BR>\n" );
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document.write( "monthly charge is 200.\r<BR>\n" );
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document.write( "this is paid regardless of the number of kilowatt hours used.\r<BR>\n" );
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document.write( "the per kilowatt charge is 1.25 for the first 600 kilowatt hours and 2.51 per kilowatt hour for any kilowatt hours over 600.\r<BR>\n" );
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document.write( "with that understanding.....\r<BR>\n" );
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document.write( "if you used 599 kilowatt hours in a month, then your monthly charge would be 200 + 1.25 * 599 = 948.75\r<BR>\n" );
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document.write( "if you used 2600 kilowatt hours in a month, then your monthly charge would be 200 + 1.25 * 600 + 2.51 * (2600 - 600) = 5719.\r<BR>\n" );
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document.write( "the general equation would be a piecemeal function that would be:\r<BR>\n" );
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document.write( "c(x) = 200 + 1.25 * x for x <= 600.<BR>\n" );
document.write( "c(x) = 950 + 2.51 * (x - 600) for x > 600.\r<BR>\n" );
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document.write( "the function would be applied as follows:\r<BR>\n" );
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document.write( "if x <= 600, then the first function would be applied.<BR>\n" );
document.write( "if x > 600, then the second function would be applied.\r<BR>\n" );
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document.write( "when 599 kilowatt hours were used, the first function would be applied to get 200 + 1.25 * 599 = 948.75\r<BR>\n" );
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document.write( "when 2600 kilowatt hours were used, the second function would be applied to get 950 + 2.51 * (2600 - 600) = 5970.\r<BR>\n" );
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