document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112919>Question 112919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of a 35% alcohol solution shoud be mixed with 2 liters of a 60% alcohol solution to produce a 50% alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82251 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .35X+.60*2=.50(X+2)<BR>\n" );
document.write( ".35X+1.2=.5X+1<BR>\n" );
document.write( ".35X-.5X=1-1.2<BR>\n" );
document.write( "-.15X=-.2<BR>\n" );
document.write( "X=-.2/-.15<BR>\n" );
document.write( "X=1.3333 LITERS OF 35% ALCOHOL IS NEEDED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".35*1.3333+.6*2=.5(1.3333+2)<BR>\n" );
document.write( ".4667+1.2=.5(3.3333)<BR>\n" );
document.write( "1.667=1.667<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );