Algebra.Com's Answer #822458 by ikleyn(52781)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
.
\n" );
document.write( "A committee of 4 people is to be selected from a group of 5 men and 7 women. If the selection
\n" );
document.write( "is made randomly, what is the probability the committee will consist of 2 men and 2 women
\n" );
document.write( "~~~~~~~~~~~~~~~\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "\r\n" );
document.write( "5 + 7 = 12 people.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "In all,  =  = 495 combinations are possible of 12 people taken 4 at a time.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It is the full size of the space of events in this problem.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Of them,  = 10*21 = 210 quadruples consists of two men and two women: they are favorable quadruples in this problem.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "THEREFORE, the probability under the problem's question is\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " P =  =  =  = 0.4242... = 0.4242 = 42.42% (rounded). ANSWER\r\n" );
document.write( " \r
\n" );
document.write( "\n" );
document.write( "Solved.\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( " |