document.write( "Question 1190737: During the war one truck out of nine was destroyed due to bombardment. What was the probability that exactly three out of six trucks would arrive safely ? \n" ); document.write( "
Algebra.Com's Answer #822450 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "During the war one truck out of nine was destroyed due to bombardment. \n" ); document.write( "What was the probability that exactly three out of six trucks would arrive safely ? \n" ); document.write( "~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "It is a typical binomial distribution problem.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The probability of the success (arrive safely) in each single trial is 1/9 = 0.111111.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The number of trials is n= 6; the number of successful trials is k= 3.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The formula for the probability is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " P(n= 6; k= 3; p= 0.111111) =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |