document.write( "Question 1190737: During the war one truck out of nine was destroyed due to bombardment. What was the probability that exactly three out of six trucks would arrive safely ? \n" ); document.write( "
Algebra.Com's Answer #822450 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "During the war one truck out of nine was destroyed due to bombardment.
\n" ); document.write( "What was the probability that exactly three out of six trucks would arrive safely ?
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document.write( "It is a typical binomial distribution problem.\r\n" );
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document.write( "The probability of the success (arrive safely) in each single trial is 1/9 = 0.111111.\r\n" );
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document.write( "The number of trials is  n= 6;  the number of successful trials is  k= 3.\r\n" );
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document.write( "The formula for the probability is\r\n" );
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document.write( "    P(n= 6; k= 3; p= 0.111111) = \"C%5B6%5D%5E3%2A0.111111%5E3%2A%281-0.111111%29%5E%286-3%29\" = \"20%2A0.111111%5E3%2A0.888889%5E3\" = 0.019268316,  or  0.01927  (rounded).    ANSWER\r\n" );
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